Two cells of emf E 1 and E 2 (E 2 > E 1 ) are connected in series in a secondary circuit of a potentiometer experiment for determination of emf. The balancing length is found to be 825 cm. Now when the terminals of cell of emf E 1 are reversed, then the balancing length is found to be 225 cm. The ratio of E 1 and E 2 is, then-
Text Solution
Verified by ExpertsThe correct answer is:
B
and 

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A silicon speciman is made into a P-type semi-conductor by dopping, on an average, one Indium atom …
The typical ionisation energy of a donor in silicon is
A 2V battery is connected across the points A and B as shown in the figure given below. Assuming th…
The diode used in the circuit shown in the figure has a constant voltage drop of 0.5 V at all curre…
For a transistor amplifier in common emitter configuration for load impedance of 1 k Ω Ω (h fe = 50…
In semiconductor the concentrations of electrons and holes are 8 × × 10 18 /m 3 and 5 × × 10 18 /m …